Optimal. Leaf size=35 \[ \text {Int}\left (\frac {1}{(a g+b g x) \left (B \log \left (\frac {e (a+b x)}{c+d x}\right )+A\right )^2},x\right ) \]
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Rubi [A] time = 0.08, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {1}{(a g+b g x) \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )^2} \, dx \]
Verification is Not applicable to the result.
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Rubi steps
\begin {align*} \int \frac {1}{(a g+b g x) \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )^2} \, dx &=\int \frac {1}{(a g+b g x) \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )^2} \, dx\\ \end {align*}
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Mathematica [A] time = 0.63, size = 0, normalized size = 0.00 \[ \int \frac {1}{(a g+b g x) \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )^2} \, dx \]
Verification is Not applicable to the result.
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fricas [A] time = 0.60, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {1}{A^{2} b g x + A^{2} a g + {\left (B^{2} b g x + B^{2} a g\right )} \log \left (\frac {b e x + a e}{d x + c}\right )^{2} + 2 \, {\left (A B b g x + A B a g\right )} \log \left (\frac {b e x + a e}{d x + c}\right )}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (b g x + a g\right )} {\left (B \log \left (\frac {{\left (b x + a\right )} e}{d x + c}\right ) + A\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 1.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\left (b g x +a g \right ) \left (B \ln \left (\frac {\left (b x +a \right ) e}{d x +c}\right )+A \right )^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.00, size = 0, normalized size = 0.00 \[ d \int \frac {1}{{\left (b c g - a d g\right )} B^{2} \log \left (b x + a\right ) - {\left (b c g - a d g\right )} B^{2} \log \left (d x + c\right ) + {\left (b c g - a d g\right )} A B + {\left (b c g \log \relax (e) - a d g \log \relax (e)\right )} B^{2}}\,{d x} - \frac {d x + c}{{\left (b c g - a d g\right )} B^{2} \log \left (b x + a\right ) - {\left (b c g - a d g\right )} B^{2} \log \left (d x + c\right ) + {\left (b c g - a d g\right )} A B + {\left (b c g \log \relax (e) - a d g \log \relax (e)\right )} B^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [A] time = 0.00, size = -1, normalized size = -0.03 \[ \int \frac {1}{\left (a\,g+b\,g\,x\right )\,{\left (A+B\,\ln \left (\frac {e\,\left (a+b\,x\right )}{c+d\,x}\right )\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {c + d x}{A B a d g - A B b c g + \left (B^{2} a d g - B^{2} b c g\right ) \log {\left (\frac {e \left (a + b x\right )}{c + d x} \right )}} - \frac {d \int \frac {1}{A + B \log {\left (\frac {a e}{c + d x} + \frac {b e x}{c + d x} \right )}}\, dx}{B g \left (a d - b c\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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